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kramer
3 years ago
14

Fernando gave Maria the following puzzle: I am thinking of a number. I divide it by 3. Then I divide the result by 5. The final

result is 8. What is my number?
Mathematics
2 answers:
LuckyWell [14K]3 years ago
7 0

To find the number we do the inverse of division, and that's multiplication. We multiply 8 x 5 x 3 to get 120, that's our number. So Fernando is thinking of the number 120, and we can prove that it's correct by dividing 120 / 3 then the result divide it by 5 and we get 8.


charle [14.2K]3 years ago
5 0
Simple, if you have the ending number as 8;

You divided it by 5. So go in reverse, and multiply by 5.

8*5=40

Then, do the same thing again, you divided it by 3, so multiply by 3.

40*3=120.

Thus, the number that Fernando gave to Maria is 120.
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Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

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Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

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<em>Hence, the smallest sum is 2</em>

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