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JulijaS [17]
3 years ago
10

Y values Range: Domain:

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

I don't know what your question means, but I'm going to say that the Domain and range of the graph is all real numbers.

Step-by-step explanation:

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I will mark u as the brainliest I will mark u as the brainiest if u get this correct thx x
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Answer:

260

Step-by-step explanation:

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Divide using long division. 6x^3+4x^2+3x+2/ 3x+2
12345 [234]

Answer: 2x² + 1

<u>Explanation:</u>

          <u>  2x²  +  0x  +  1     </u>

3x + 2 ) 6x³ + 4x² + 3x + 2

         - <u>(6x³ + 4x²</u>)    ↓     ↓

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                             - <u>(3x + 2)</u>

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5 0
3 years ago
Sarah's water bottle holds 500 milliliters. Shawn container holds 4/5 as much water. How many total milliliters of water do both
tamaranim1 [39]
900 milliliters combined
6 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
4 years ago
What is the real part of the complex number when 4 plus 5i is multiplied with 2 minus i?
Nady [450]

Answer:

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Step-by-step explanation:

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