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2 years ago

Subtract the rational expression and simplify x+2/2x-6 - x+3/5x-15

Mathematics

1 answer:

SashulF [63]2 years ago

7 0

Answer: -3x² - 2x -57

This is how this would look: $\frac{x+2}{2x-6} - \frac{x+3}{5x-15}$

First I brought the denominator to the top for both expressions.

so I was left with: 2x-6(x+2) - 5x-15(x+3)

I distributed, combined like terms, and simplified.

<em><u> -3x² - 2x -57</u></em> was my answer

Step-by-step explanation:

Trust Milky. Milky smart.

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Question is in the picture.

Elza [17]

Answer:

It should be d=2.25t

Step-by-step explanation:

The question only contains 2.25 not 2 or 4 and also you would multiply it

3 0

2 years ago

Can somebody tell me how to solve these kind of problems?

Ugo [173]

Answer: 918km^2

Step-by-step explanation:

$area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8$

Let x be the new dimension of the area;

$x=a-(a*p*y)$

$x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2$

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2 years ago

Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g

olchik [2.2K]

If $x$ is the first number in the progression, and $r$ is the common ratio between consecutive terms, then the first four terms in the progression are

$\{x,xr,xr^2,xr^3\}$

We want to have

$\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}$

In the second equation, we have

$xr^3-xr=xr(r^2-1)=36$

and in the first, we have

$xr^2-x=x(r^2-1)=12$

Substituting this into the second equation, we find

$xr(r^2-1)=12r=36\implies r=3$

So now we have

$\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32$

Then the four numbers are

$\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}$

4 0

2 years ago

I need help with number 15,16,and 17

777dan777 [17]

15. A=7, 16. V=9, 17. D=26

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2 years ago

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Harlamova29_29 [7]

lol, that would be biology

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2 years ago