$A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}$

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

$\sqrt5$

used $(\sqrt{a})^2=a$ for a ≥ 0.

$AB^2+BC^2=AC^2$ therefore ΔABC is a right triangle.

6 0

3 years ago

Examine the rotation. Which best describes point D?

Nadusha1986 [10]

We can’t see the rotation

6 0

3 years ago

Read 2 more answers

Jenny picked 25 roses. she gave away 10 roses. What percent of the roses did Jenny give away?

diamong [38]

Divide 10 by 25, which would get you 4. Move the decimal over two to the left, because you wanted a percentage.

Jenny gave away 40% of the roses.

3 0

3 years ago

Geometry review question ​

Geometry review question