All categories

2 years ago

Myra combined the like terms in the algebraic expression correctly.

Mathematics

2 answers:

NeX [460]2 years ago

7 0

Answer:

Myra combined the like terms in the algebraic expression correctly. Which statement correctly describes what Myra did?

8 x squared + 7 minus 2 x squared + x

Myra combined 8 and Negative 2 to equal 6 x squared + x + 7.

Step-by-step explanation:

olga55 [171]2 years ago

5 0

The answer would be the first one, combining 8 and -2

This is because the 2 like terms are 8x^2 and -2x^2. You can get this by looking in the problem. There are 2 terms with x^2 which means we have to combine them. One of them is 8x^2 (the 1st one) and the other is -2x^2 (since it says 7-2x^2)

If you combine these you will get 6x^2 [8+(-2)=6]

You might be interested in

Find the value of this expression if x = -9. x2 + 1 x+7

Mamont248 [21]

Answer:

-41

Step-by-step explanation:

You would replace all x's with -9 and solve.

6 0

3 years ago

8 is what percent of 2500

Nataly [62]

8 percent of 2500 is 200.

5 0

3 years ago

Read 2 more answers

HELPSDBNENANSSnshejs

Ganezh [65]

I WILL TRY AND FIGURE IT OUT RQ

4 0

2 years ago

Read 2 more answers

If 23/8, 11/2, 9/6, and 15/7 are placed in order from least to greatest, which would be first?

yarga [219]

Answer:

$\frac{9}{6}$

Step-by-step explanation:

The given fractions are;

$\frac{23}{8},\frac{11}{2},\frac{9}{6},\frac{15}{7}$

The least common denominator is $168$ .

We express all the fractions in equivalent form with the LCD as the denominator.

$\frac{23}{8}=\frac{21\times23}{21\times8}=\frac{483}{168}$

$\frac{11}{2}=\frac{84\times11}{84\times2}=\frac{924}{168}$

$\frac{9}{6}=\frac{28\times9}{28\times6}=\frac{252}{168}$

$\frac{15}{7}=\frac{24\times15}{24\times7}=\frac{360}{168}$

We now compare the equivalent forms and arrange from the least to the greatest.

$\frac{252}{168}\:$

This implies that,

$\frac{9}{6}\:$

Therefore the first would be $\frac{9}{6}$ .

8 0

2 years ago

Find the midpoint between points (-4,2) and (2,-2) (1,-1) (0,-1) (-1,0) (1,0)

djverab [1.8K]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad 
(\stackrel{x_2}{2}~,~\stackrel{y_2}{-2})
\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{2-4}{2}~~,~~\cfrac{-2+2}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{0}{2} \right)\implies (-1~,~0)$

3 0

3 years ago