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tatuchka [14]
3 years ago
7

How to do mixed number math

Mathematics
1 answer:
Naddik [55]3 years ago
3 0
2 and 3/4 is a mixed number and the decimal of it is 2.75 
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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st
Naily [24]

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

4 0
2 years ago
From the parking lot at red hill shopping center the angle of the top of the hill is about 25 from the base of the hill the angl
eimsori [14]

Answer:

512 ft.

Step-by-step explanation:

From the parking lot at the Red Hill Shopping Center, the angle of sight (elevation) to the top of the hill is about 25. From the base of the hill you can also sight the top but at an angle of 55. The horizontal distance between sightings is 740 feet. How high is Red Hill? Show your subproblems.

Solution:

Let x be the distance from the base of the hill to the middle of the hill perpendicular to the height, let h be the height of the hill. Therefore:

tan 25 = h/(x + 740)

h = (x + 740)tan 25       (1)

tan 55 = h / x

h = x tan 55        (2)

Hence:

(x + 740)tan 25 = xtan 55

0.4663(x + 740) = 1.428x

0.4663x + 345.07 = 1.428x

0.9617x = 345.07

x = 359 ft.

h = xtan55 = 359 tan(55) = 512 ft.

8 0
2 years ago
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
Harrizon [31]

Answer:

x^{1} wives

x^{2} sacks

x^{3} cats

x^{4} kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

x^{1} wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

x^{2} sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

x^{3} cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

x^{4} kits

8 0
2 years ago
Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.
VladimirAG [237]
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
7 0
2 years ago
Which of the following is the graph of (x + 3)2 + (y - 1)2 = 9? A B с 2. 2 2 2 4 -2 4 2 -2 2 2 4 2.​
Zarrin [17]

The third one is the correct graph for the equation

hope it helps !!

5 0
2 years ago
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