All categories

3 years ago

Round 446,662 to the nearest hundred thousand

Mathematics

2 answers:

Fudgin [204]3 years ago

6 0

Answer:

400,000

Step-by-step explanation:

446 is the closest to 400 so 400,000

pls mark brainliest

andrey2020 [161]3 years ago

6 0

Answer:

400,000 is the correct answer

Step-by-step explanation:

just round the 4.

You might be interested in

Engineering An overpass intersects two

JulijaS [17]

Answer:

they are already paralell

Step-by-step explanation:

4 0

3 years ago

Unit 8 triangles and trigonometry quiz 8-2 please help me with all

Sedbober [7]

Answer:

i think 6

Step-by-step explanation:

hope this helps

5 0

3 years ago

123456789101112131415161718

lesya692 [45]

Answer:

the third one is the correct answer

Step-by-step explanation:

hope that helps

7 0

3 years ago

Which values are solutions of the equation? Check all of the boxes that apply.

Vladimir [108]

in order to answer, we need to know what is the equation?

4 0

3 years ago

Read 2 more answers

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago