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stiks02 [169]
3 years ago
10

Engineering An overpass intersects two

Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

they are already paralell

Step-by-step explanation:

ok

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For a sequence defined by f(1)=13 and 2f(n-1)+(n-2), which of the following is the value of f(4)
densk [106]
Given that:
f(1)=13 and 2f(n-1)+(n-2)
then:
f(4) will be found as follows:
f(2)=2f(2-1)=2f(1)=2*13=26
f(3)=2f(3-1)+(3-2)=2f(2)+1=2*26+1=53
f(4)=2f(4-1)+(4-2)=2f(3)+(4-2)=2(53)+2=108

Thus:
Answer:(3) 108

6 0
3 years ago
I have four times as much money as my brother has. Our total is $55. How much does each of us have?
padilas [110]

Answer:

27.5

Step-by-step explanation:

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3 years ago
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How deep is the hole at ground level
tia_tia [17]
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3 years ago
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Angie and Brian are running a bakery. They are going to make three kinds of banana bread: regular, one with extra sugar, and one
dolphi86 [110]

Answer:

150 regular loaves

125 loaves with extra sugar

100 loaves with extra bananas.

Step-by-step explanation:

Let R represent loaves of regular bread, S represent loaves with extra sugar, and B represent loaves with extra bananas. If they have 1200 bananas, 1050 cups of sugar, and 1075 cups of flour available, the number of each type of bread that Angie and Brian can make are given by the following system of equations:

3R+2S+5B=1,200\\3R+4S+1B=1,050\\2R+3S+4B=1,075

Solving the linear system:

3R+4S+1B-(3R+2S+5B)=1,050-1,200\\2S-4B=-150\\S=-75+2B\\\\3R+2*(-75+2B)+5B=1,200\\2R+3*(-75+2B)+4B=1,075\\3R+9B=1,350\\2R+10B=1,300\\\\3R+9B-1.5*(2R+10B)=1,350-(1.5*1,300)\\9B-15B=-600\\B=100\\2R+10*100=1,300\\R=150\\3*150+2S+5*100=1,200\\S=125

They should make 150 regular loaves, 125 loaves with extra sugar, and 100 loaves with extra bananas.

7 0
3 years ago
Hi! I was wondering if you could help with this question please :)​
Makovka662 [10]

Answer:

R=\frac{QJ}{I^2t}

Step-by-step explanation:

So we have the equation:

Q=\frac{I^2Rt}{J}

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

(J)Q=(J)\frac{I^2Rt}{J}

Simplify the right:

JQ=I^2Rt

We can rewrite our equation as:

JQ=R(I^2t)

So, to isolate the R variable, divide both sides by I²t:

\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}

The right side cancels, so:

R=\frac{QJ}{I^2t}

And we are done!

7 0
3 years ago
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