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sammy [17]
3 years ago
15

Which is the graph of f(x) = 4[1/2]x ?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0

Step-by-step explanation:

answer is in picture see

hope it helpful

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The sum of two consecutive even integers is 122. what are the integers?​
Volgvan

Answer:

If the numbers were the same, they'd both be 61

So, try 60 and 62.

x + x+2 = 122

2x = 120

x = 60

Hope that helps!

4 0
3 years ago
Read 2 more answers
The frequency table shows the scores from rolling a dice<br><br> work out the mean
umka2103 [35]
You have to add all of your frequency’s together and divide by 6 for the 6 scores. your mean would be 2
6 0
2 years ago
Find the height of the cylinder whose radius is 7cm and tsa is 96cm2
Advocard [28]

Answer:

0.62

Step-by-step explanation:

Height = Volume / πr²

7 0
3 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ &lt; 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

6 0
3 years ago
Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)
Daniel [21]

The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

5(x-2) + (-9) = -7(1-x)

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x

Solve for terms in left hand side of equation

5x - 19 = -7+7x

Move the variables to one side and constants to other side

7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6

Thus the solution for equation is x = -6

8 0
3 years ago
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