Answer:.
W. T. F.
it has nothing to do with a dog!?!?!?!?!!?!?!?!?!?!?
Given:
The values are
.
To find:
The values of
and
.
Solution:
We have,

...(i)
Multiply both sides by 10.
...(ii)
Subtracting (i) from (ii), we get




And,



Now, the product of a and b is:


The quotient of a and b is:



Therefore, the required values are
and
.
To determine the effect of changing the diameter of a sphere to its volume, we would need to know the formula for the volume of a sphere which is V = 4πr³/3 where r is half of the diameter. As you can see, there is a direct relationship.
r1 = d1/2
r2 = d2/2 = 2d1/2 = d1
V2/V1 = (4πd1³/3) / (4π(d1/2)³/3)
V2/V1 = 8
Therefore, the volume of the sphere would be 8 times the original volume.
Answer:
- If the sum is 6, a small cone will be ordered.
- If the sum is 8 or 9, a medium cone will be ordered.
- If the sum is 11, a large cone will be ordered.
Step-by-step explanation:
The table below shows the possible outcomes from drawing two balls. We see the relative frequencies to be ...
6: 4
8: 2
9: 2
11: 4
To make a fair decision, we want the relative frequencies of the decision possibilities to be the same. If we combine sums 8 and 9 to one category (medium cone, for example), then 6, (8 or 9), and 11 will all have the same relative frequency: 4.
The appropriate "fair decision" choice is ...
6: small cone
8 or 9: medium cone
11: large cone
= 12*5 + 12*3i - 5*2i - 6i^2 (remember that i^2 = -1) so:-
= 60 +26i - 6*(-1)
= 60 + 26i + 6
= 66 + 26i