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Paco, the class president, surveys 280 students about the prices in the school cafeteria 70% of

Phantasy [73]

Answer:

196 people want lower prices

Step-by-step explanation:

6 0

3 years ago

Find five consecutive integers whose sum is 195

ycow [4]

$n;\ n+1;\ n+2;\ n+3;\ n+4-five\ consecutive\ integers\\\\(n)+(n+1)+(n+2)+(n+3)+(n+4)=195\\n+n+1+n+2+n+3+n+4=195\\5n+10=195\ \ \ \ \ |subtract\ 10\ from\ both\ sides\\5n=185\ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\n=37\\\\Answer:\boxed{37;\ 38;\ 39;\ 40;\ 41}$

7 0

3 years ago

Read 2 more answers

Whats the solutions!?? look at the picture

gtnhenbr [62]

Answer:

3/x=y

Step-by-step explanation:

if not am sorry

6 0

3 years ago

There is one error in one of five blocks of a program. To find the error, we test three randomly selected blocks. Let X be the n

Molodets [167]

<span>The probability, or expectation value for X in a block, equals the number of occurrences of X in all the blocks divided by the total number of blocks

</span>

well E(X)=µ and

Var(X)=E[(X-µ)^2]

7 0

3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$