As the inspection machine detect and discard any part that is completely defective, only the good and partially defective parts passed this inspection.

Then, if we have:

Probability of being a good part P(G)=0.90

Probability of being a patially defective part P(P)=0.02

Probability of being a completely defective part P(D)=0.08.

Probability of passing the inspection machine = 1-P(D)=1-0.08=0.92

Then, the probability of having a good part, given that it passed the inspection machine is:

$P(G|Pass)=P(G)/P(Pass)=0.90/0.92=0.978$

4 0

3 years ago

Last questions on this quiz (I always get confused on finding the x value)

zimovet [89]

For the first one, we know that is a right angle. right angles are 90 degrees. if we subtract 90 - 49 that equals 41. so the second value needs to equal 41. since we have a 3 there already, we are going to subtract 41-3, which is 38. x = 38

3 0

2 years ago

Help me please I don’t get it

svet-max [94.6K]

The answer to B is: HP, HE, H and O, HH, OO, EE, PP, PE, PO, and EO

the answer to a would be 10

4 0

3 years ago

Read 2 more answers