Since Sylvanite only contains 28% gold by mass, then to obtain 81.0 grams of gold, x amounts of sylvanite must be mined. To determine x, we divide 81 grams by 28%. This equation is shown below:
0.28X = 81
X = 81/0.28
X = 289.29 grams
Therefore, 289.29 grams of sylvanite must be dug up to obtain 81 grams of gold.
the expression is 27a^3 or (3a)^3
It is true. The triangles are congruent.
Let the number total slices = x
He ate (1/4) x
He has x - 1/4 x = 3/4 x slices left.
Each one of these slices is cut into 1/8s
T (total number of slices) = 8 * (3/4x)
T = (8*3/4) x
T = (24/4)x
T = 6x slices.
