Answer: 15/91 which is choice B
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There are two methods to find this answer.
Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91
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Method 2) We can use the nCr combination formula. Order does not matter.
We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)
Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)
So that's another way to get the answer 15/91.
Hello!
1 pound = $3.50
To find the cost of 512 pounds, we must multiply the cost per pound by the total amount of pounds:
3.50 * 512 = 1,792
ANSWER: The total cost of the chicken was $1,792.
Answer:
y=9/2x+2
Step-by-step explanation:
Domain is the numbers yo can use
we has a sqrt and a ln
we cant have any neagtive ln's or sqrts
x cannot be negative
it cannot be 0 either
domain is all numbers bigger than 0
deritivive
apply chain rule
dy/dx(f(g(x))=f'(g(x))g'(x)
and also
dy/dx (lnx)=1/x
and
dy/dx(f(x)g(x))=f'(x)g(x)+g'(x)f(x)
and from experience
dy/dx(sqrtx)=1/(2√x)
so
dy/dx(ln(2xsqrt(2+x)))=
(1/(2xsqrt(2+x))(2)(sqrt(2+x)+(x/(2sqrt(2+x))=
(3x+4)/(2x(x+2))
domain is all real numbers greater than 0
derivitive is
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°