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gogolik [260]
3 years ago
11

Write an explicit formula for a_na

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

7n + 18

Step-by-step explanation:

it goes up in 7 so 7n and 25-7 =18

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And please explain it?
Brums [2.3K]
You probably jsut need to use law of cosines in order to solve for angle A

c^2 = a^2+b^2 -2ab \cos C
or
a^2 = c^2+b^2 -2cb \cos A
4 0
4 years ago
The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
3 years ago
−28=19 solve to this question
anygoal [31]

Answer:

i think u missed out the missing variable

Step-by-step explanation:

4 0
3 years ago
Solve for the variable m. m-n=5
dolphi86 [110]

if you wanna solve for m you have get m by him self.

m-n = 5

m-n+n = 5+n

m = 5+ n

there is your answer. hope it is heplful

6 0
3 years ago
From the equation y=3.5x identify the constant of proportionality
Ilya [14]

Answer:

3.5

Step-by-step explanation:

5 0
3 years ago
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