Please help If you can

Line segment YV of rectangle YVWX measures 24 units.

oksian1 [2.3K]

Answer: $YX=13.85\ units$

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

$WV=YX\\\\YV=XW=24$

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You can identify that:

$\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24$

Therefore, in order to find the length of the segment YX, you must substitute values into $tan\alpha =\frac{opposite}{adjacent}$ and then you must solve for YX.

You get that this is:

$tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85$

7 0

3 years ago

Read 2 more answers

Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,

NARA [144]

Answer:

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

Step-by-step explanation:

The six measurements are:

202, 164, 157, 177, 113, 213

Sample mean:

Sum of all values divided by the number of values which is 6. So

$S_m = \frac{202+164+157+177+113+213}{6} = 171$

Sample standard deviation:

Square root of the difference squared between each value and the mean, and divided by 1 subtracted by the sample size. So

$s = \sqrt{\frac{(202-171)^2+(164-171)^2+(157-171)^2+(177-171)^2+(113-171)^2+(213-171)^2}{5}} = 35.69$

Confidence interval

We have the standard deviation for the sample, which means that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 3.365

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.365\frac{35.69}{\sqrt{6}} = 49$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 171 - 49 = 122 ppm

The upper end of the interval is the sample mean added to M. So it is 171 + 49 = 220 ppm

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

8 0

3 years ago

What is 2/3x + 15= 17?

STatiana [176]

2/3x + 15= 17

subtract 15 from each side

2/3 x +15 -15 = 17-15

2/3 x =2

multiply by 3/2

3/2* 2/3 x = 2 * 3/2

x = 3

4 0

3 years ago

Please help ;-; very urgent

NARA [144]

Looks like you got the answer allready selected in the photo

5 0

3 years ago

Surface area of pyramids

Vladimir79 [104]

Multiply the side length of the base by the slant height and divide by two. Then, multiply by 4. This will give you the lateral surface area of the pyramid. Add the base surface area and the lateral surface area. Hope this helps you out

6 0

4 years ago