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4vir4ik [10]
2 years ago
8

The Hamid family installed a cylindrical pool in their backyard. The

Mathematics
1 answer:
Alex787 [66]2 years ago
4 0

Answer:

4,046.4 ft^{2}

Step-by-step explanation:

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-0.625

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Write three examples of decimals that have a 5 I the hundredths place
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The first number in front of the decimal (.), is in the tenths place. The number after the tenth place is the hundredth place. After that is the thousandths and it keeps going.
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tia_tia [17]

Answer:

A. 7

Step-by-step explanation:

h(x)=2x + 4

2(7)=14

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2 years ago
Precalc - trig identities. Decent explanation, please. THX!!!
LuckyWell [14K]

12. Recall the half-angle identity,

\sin^2\dfrac y2=\dfrac{1-\cos y}2\implies\sin\dfrac y2=\sqrt{\dfrac{1-\cos y}2}

where we take the positive square root because y is an angle in a right triangle, which means 0^\circ, so 0^\circ. For such an angle, it's always the case that \sin\dfrac y2>0.

Use the Pythagorean theorem to find the length of the hypotenuse:

\sqrt{5^2+12^2}=\sqrt{169}=13

Then

\sin\dfrac y2=\sqrt{\dfrac{1-\frac5{13}}2}=\sqrt{\dfrac4{13}}=\dfrac2{\sqrt{13}}

###

13. x is in quadrant II, which means 90^\circ, so 45^\circ. In other words, \dfrac x2 is in quadrant I, so \sin\dfrac x2>0. From the half-angle identity we get

\sin\dfrac x2=\sqrt{\dfrac{1-\cos x}2}=\sqrt{\dfrac23}

###

14. Simplification follows from the definitions of each function:

\sec x=\dfrac1{\cos x}

\tan x=\dfrac{\sin x}{\cos x}

\csc x=\dfrac1{\sin x}

So we have

\sec x\tan x\cos x\csc x=\dfrac{\sin x\cos x}{\cos^2x\sin x}=\dfrac1{\cos x}

###

15. Use the Pythagorean identity:

\cos^2x+\sin^2x=1\implies\dfrac{\cos^2x}{\cos^2x}+\dfrac{\sin^2x}{\cos^2x}=\dfrac1{\cos^2x}\implies1+\tan^2x=\sec^2x

Then

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6 0
2 years ago
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