Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
7ab + 5 is going to be the answer because I solved it and that's the answer
Answer:
x=1
Step-by-step explanation:
By factoring, you'll compress the equation to (x-1)^2=0
Next take out the square: x-1=0
Now subtract one to the other side to get x! x=1
Hope this helps! :)
Answer:
See below
Step-by-step explanation:
(0,16) - y axis
(2, -12) - IV
(-1, 2) - II
(3, 0) - x axis
(36.7, 3.9) quadrant I
(-5/8, -5 1/3) - III
Answer:
And what cuase might that be...? Jkjk ofc ill help
Step-by-step explanation:
Amswer is C. im 99 percent sure i did the math and to double check i put it into a site ans it said it was C! Hope this helps! :)
