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pav-90 [236]
3 years ago
13

Which equation represents a line which is perpendicular to the line y = 5x - 8?

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0
When two equations are perpendicular their slopes are 90° apart. In the equation y=5x-8 the slope is 5. The perpendicular slope is negative and the inverse of the given slope. So in this case the perpendicular line will have the slope = - 1/5
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Kryger [21]
The eight pound bag of dog food is better.
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3 years ago
Read 2 more answers
1/3 x + y = 4 solve for y
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Y=4
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4x + 2y = -12 3x + y = -10 please help system by substitution.
padilas [110]

Answer:

(-4, 2)

Step-by-step explanation:

4x+2y=-12

3x+y=-10

Start by dividing the first equation by 2 to simplify it...

2x+y=-6

Then, subtract -2x from both sides to isolate y...

y=-2x-6

Substitute -2x-6 for y in the second equation...

3x-2x-6=-10

Combine like terms...

x-6=-10

Add 6 to both sides

x-6+6=-10+6

x=-4

Plug -4 in for x to solve for y:

3(-4)+y=-10

-12+y=-10

Add 12 to both sides

-12+12+y=-10+12

y=2

(x,y)=(-4,2)

3 0
2 years ago
Write the slope-intercept form of the equation of the line through the given point and slope.
Mandarinka [93]

Answer:

y=-4x+1

Step-by-step explanation:

Graph (1,-3)

Go down 4 over one/ up left one

Get y-intercept

Then BOOM you got it

8 0
2 years ago
The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.
gtnhenbr [62]

Answer:

a) r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=4 \sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501  

r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5  

And the slope would be:  

m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

And we can find the intercept using this:  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

4 0
3 years ago
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