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Sophie [7]
3 years ago
6

A store sells USB flash drives for 25$ each. The mark up fo each USB flash drive is 25%. How much did the stor pay for 50 memory

cards
Mathematics
2 answers:
Stolb23 [73]3 years ago
5 0

Answer:

  • $1000

Step-by-step explanation:

<u>Given</u>

  • SP = $25
  • SP = CP + 25% = 1.25CP

<u>Find cost price for each memory card</u>

  • 25 = 1.25CP
  • CP = 25/1.25
  • CP = 20

<u>The store paid for 50 memory cards</u>

  • $20*50 = $1000
Tanya [424]3 years ago
3 0

Answer:

1000$

Step-by-step explanation:

Given

SP = $25

SP = CP + 25% = 1.25CP

Find cost price for each memory card

25 = 1.25CP

CP = 25/1.25

CP = 20

The store paid for 50 memory cards

$20*50 = $1000

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In a class 30 of students, 13 have a cat and 7 have a dog. There are 4 students who
AVprozaik [17]

Answer:

4/13

Step-by-step explanation:

"given that they  have a cat?" means you  are referring to only the students that have cats(that is the number on the bottom)

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7 0
3 years ago
The sum of 28+29+42=99. So what addition property was used Commutative, associative, identity, or distributive ?
IrinaVladis [17]

28 + 29 + 42 = 28 + 42 + 29 = 99

Commutative property: a + b = b + a

3 0
4 years ago
The point P(21,35) is on the terminal side of an angle in standard position. What is the distance from P to the origin?
Ira Lisetskai [31]

Answer:

The distance from P to origin is approximately 40.82 units.                                  

Step-by-step explanation:

We are given the following in the data:

The point P(21,35)

We have to find the distance of point P from the origin.

Coordinates of origin: (0,0)

Distance formula:

(x_1,y_1),(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

Putting the values, we get,

(21,35), (0,0)\\\\d = \sqrt{(0-21)^2 + (0-35)^2} = \sqrt{1666} = 7\sqrt{34} \approx 40.82\text{ units}

The distance from P to origin is approximately 40.82 units.

7 0
4 years ago
Can someone put a website to help me understand this?
Alenkinab [10]

Answer:

67

Step-by-step explanation:

Since the diagonals in a rectangle are congruent, AC=BD and

7x+18=10x-3

We need to separate x -- to do that, we can first subtract 7x from both sides, resulting in

18=3x-3

Next, add 3 to both sides to get

21=3x

Divide both sides by 3 to get

x=7

Then, we just plug x into 10x-3 to get BD = 7*10-3 = 67

7 0
3 years ago
Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20
Mice21 [21]

Power and chain rule (where the power rule kicks in because \sqrt x=x^{1/2}):

\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'

Simplify the leading term as

\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}

Quotient rule:

\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}

Chain rule:

(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)

(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)

Put everything together and simplify:

\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}

=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}

=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}

=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}

=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}

=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}

=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}

5 0
3 years ago
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