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Zepler [3.9K]
4 years ago
13

Jeff weighed 190 pounds and lost 1/4 pound each week. Allan weighed 127 pounds and gained 5/8 pound each week. After how many we

eks did they weigh the same?​
Mathematics
1 answer:
STatiana [176]4 years ago
5 0

Answer:

oh i did this let me find my book

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If f(x)=3x-4 and g(x)=x+2, find (f-g)(x)
Paha777 [63]
You would set your equation up as basically f(x)-g(x), so:
(3x-4)-(x+2)
combine your like terms and you should have your answer:
2x-6
3 0
3 years ago
Read 2 more answers
WILL GIVE A CROWN...A polygon is shown: A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vert
strojnjashka [21]

The area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units.

In the given polygon MNOPQR, side MN is parallel to side RQ and the side MR is parallel to side PQ

We will draw a perpendicular line from point O on the side RQ, which will intersect RQ at point S. So, we can now divide the whole polygon into two different rectangles MNSR and OPQS with the areas as A₁ and A₂ respectively.

In rectangle MNSR, length(MN) = 5 units and width (MR) = 3 units

According to the formula for Area of rectangle,

A₁ = (length)×(width)

A₁ = (5 units)×(3 units)

A₁ = 15 square units

Now in rectangle MNSR, side MN= side RS and side MR = side NS,

so RS= 5 units and NS= 3 units

That means, SQ= RQ- RS = 7-5 = 2 units

and OS= NS - NO = 3- 2 = 1 unit

In rectangle OPQS, we have length(SQ) = 2 units and width(OS) = 1 unit

So, A₂ = (length)×(width)

A₂ = (2 units)×(1 unit)

A₂ = 2 square units

So, the area of polygon MNOPQR = (Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units)

4 0
4 years ago
Read 2 more answers
Imamu pays $30 each month for his gym membership. What is the change in the amount of money in his account after 2/3 of a year
Alchen [17]
The answer is $240 because 2/3 in a years have 8 month so just multiply 3*8  which give you 24 and just add a zero.

Your answer is: $240.


Thank you 

                                                                   Have a great day :).
4 0
3 years ago
What is the measure of a counterclockwise rotation about the spinnercenter that maps label i to label f? 108 72 36 252
ankoles [38]
Answer: First option 108°

Each label is equivalent to an angle of:
Angle=360°/n
Number of label: n=10
Angle=360°/10
Angle=36°

To map label i to label f in a counterclockwise rotation, we must pass by 3 regions: i to h, h to g, and g to f; each one of 36°. Then the measure of a counterclockwise rotation about the spinnercenter that maps label i to label f is:
Measure=3(36°)
Measure=108°
5 0
4 years ago
Which expression is equivalent to 3√x^5?
Elanso [62]
∛x^5 y
= (x)^5/3 y^1/3

answer
B. second option

6 0
3 years ago
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