<span>Bo is carrying a bag of topsoil that is 78 full. He drops the bag and 13 of the soil pours out onto the ground. How much of the bag of soil poured onto the ground? is the answer</span>
Answer:
260
Step-by-step explanation:
Answer:
6 mins
Step-by-step explanation:
Given that;
T(t) = Ce^-kt + T(s)
Since T(t) = 200◦F, and T(s) = 70◦F where t = 0
200= Ce^-k(0) + 70
C= 200 - 70
C = 130
Then when T(t) = 190◦F and t= 1s ;
190 = 130e^-(k *1) + 70
190 - 70 = 130e-^(k *1)
120/130 = e^k
0.923 = e^-k
-k = ln(0.923)
k = 0.08
To determine the time taken to reach a temperature of 150◦F
150 = 130e^-(0.08t) + 70
150 - 70/130 = e^-(0.08t)
0.6154 = e^-(0.08t)
-(0.08t) = ln 0.6154
0.08t = 0.4855
t = 0.4855/0.08
t = 6 mins
Answer: 1.62225 x 10^-2 or 0..0162225
Step-by-step explanation:
It would be ( 1,0 ) i took the test