Answer:
the x-intercepts are at
x = -3
x = 0
x = 1
Step-by-step explanation:
ask the points, where the functional value is 0.
2x³ + 4x² - 6x = 0
we see that every term contains an expression of x. so, we can simplify this
x × (2x² + 4x - 6) = 0
so, one solution is plainly visible : x=0
for the other solutions we need to solve the square equation
2x² + 4x - 6 = 0
or even simpler
x² + 2x - 3 = 0
the solution of a square equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a=1
b=2
c=-3
x = (-2 ± sqrt(2² - 4×1×-3))/(2×1) = (-2 ± sqrt(4 + 12))/2 =
= (-2 ± sqrt(16))/2 = (-2 ± 4)/2 = -1 ± 2
x1 = -1 + 2 = 1
x2 = -1 - 2 = -3
