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Alexxx [7]
3 years ago
14

How many trucks would you load in 9 hours if i loaded 5 trucks every 6 minutes

Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0
The answer is 270 trucks.
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If Lucas runs 5 miles in 38 minutes, what is his unit rate per minute?
Zina [86]

Answer:

1 mile every 7.6 min

Step-by-step explanation:

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3 years ago
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Ises: 1. Directions: Express in factor form a
frosja888 [35]

Answer:

10 x 10 x 10 x 10 x 10 = 100000

6 x 6 x 6 = 216

4 x 4 x 4 x 4 = 256

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 1024 / or if the number was 21 x 0  then the answer = 1

Step-by-step explanation:

I already wrote the explanation in the answer but I'm guessing the number you put beside the first number is the exponent. So as you can see 73 = 7 mulitiplying by itself 3 times. The number 3 is an exponent because it tells you how many times you're multiplying the number by itself. If you continue doing that then you will get the same answer as I did. Good luck!

6 0
3 years ago
Find the measure of b.
Lyrx [107]

Answer:

105

Step-by-step explanation:

55+50+x=180

x=75 this is the other inside angle. to find b, you need to take 75 and subtract it from 180. this is because a straight line is equal to 180 degrees

6 0
2 years ago
|x| + 6 = 3 <br><br> A question on homework
alexdok [17]

Answer:

-9

Step-by-step explanation:

-9+6=-3

5 0
3 years ago
Estimate 1 13 cos(x2) dx 0 using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. (Round your answers to six decimal
babunello [35]

Answer:

(a) 4.152698

(b) 3.215557

Step-by-step explanation:

(a)

\int\limits^{13}_1 {cos(x^2)} \, dx =M_n=$\sum_{n=1}^{\infty} f(m_i)\Delta x $

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

Now, the midpoints of these subintervals are:

\frac{1+5}{2} =3\\\\\frac{5+9}{2} =7\\\\\frac{9+13}{2} =11

Hence:

M_4= 3*(cos(3^2))+3*(cos(7^2))+3*cos((11^2))\approx 4.152698

(b)

\int\limits^{13}_1 {cos(x^2)} \, dx =T_n=\frac{\Delta x}{2} (f(x_o)+2f(x_1)+2f(x_2)+...+2f(x_n_-_1)+f(x_n))

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

The endpoints of the subintervals consist of:

5,9

Hence:

T_4= \frac{3}{2}(cos(1^2)+2*cos(5^2)+2*cos(9^2)+cos(13^2)) \approx 3.215557

8 0
3 years ago
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