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Mandarinka [93]
2 years ago
11

If a line passes through the points (2.5,2.5) and (3.5,5.5), the equation of the line is y-5.5 = 3(x- blank ). ​

Mathematics
2 answers:
tankabanditka [31]2 years ago
6 0

Answer:

4.5

Step-by-step explanation: Trust me you aint gonna get it wrong i promise

timurjin [86]2 years ago
5 0

Answer:

(x- 2.5)

Step-by-step explanation:

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Solve the system of equations -x+ 2y = –11 and 5x – 8y = 39 by<br> combining the equations.
Alchen [17]

Answer:

x=-5, y=-8. (-5, -8).

Step-by-step explanation:

-x+2y=-11

5x-8y=39

---------------

5(-x+2y)=5(-11)

5x-8y=39

---------------------

-5x+10y=-55

5x-8y=39

--------------------

2y=-16

y=-16/2

y=-8

-x+2(-8)=-11

-x-16=-11

-x=-11+16

-x=5

x=-5

3 0
2 years ago
Simplify the following expression below:
IrinaK [193]
So, 4/3 - 2i

4/3 - 2i = 12/13 + i8/13

multiply by the conjugate: 
3 + 2i/3 + 2i
= 4(3 + 2i)/(3 - 2i) (3 + 2i)
(3 - 2i) (3 + 2i) = 13

(3 - 2i) (3 + 2i)

apply complex arithmetic rule: (a + bi) (a - bi) = a^2 + b^2
a = 3, b =  - 2
= 3^2 + (- 2)^2

refine: = 13
= 4(3 + 2i)/13

distribute parentheses:
a(b + c) = ab + ac
a = 4, b = 3, c = 2i
= 4(3) + 4(2i)

Simplify:
4(3) + 4(2i)
12    +    8i


4(3) + 4(2i)
Multiply the numbers: 4(3) = 12
= 12 + 2(4i)

Multiply the numbers: 4(2) = 8
= 12 + 8i


   12 + 8i
= 12 + 8i/13

Group the real par, and the imaginary part of the complex numbers:


Your answer is: 12/13 + 8i/13





Hope that helps!!!
7 0
3 years ago
-7x-6y=-1
Xelga [282]
Cancel something
we cancel x's

multiply 1st equation by 5 and 2nd by 7 and add them
-35x-30y=-5
<u>35x-28y=7 +</u>
0x-58y=2

-58y=2
divide both sides by -58
y=-1/29
sub back
5x-4(-1/29)=1
5x+4/29=1
minus 4/29 from both sides
note, 1=29/29
5x=25/29
divide bot sides by 5 (or times 1/5)
x=5/29


(5/29,-1/29)
6 0
3 years ago
What is the answer? im trying to figure it out and its hurting my head
Naya [18.7K]
7x-99=2x+1
5x=100
x=20

mark me brainliest if the answer is correct, thank you in advance :)
3 0
3 years ago
I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
3 years ago
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