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2 years ago

14

Charlene wants to earn at least $600 this month in commission. What is the minimum amount she needs to sell to earn $600 if she

earns a 4.5% commission on everything she sells? Round to the nearest dollar.

1 answer:

nika2105 [10]2 years ago

3 0

Answer:

She will need to earn a little more than $1333 that week.

Step-by-step explanation:

600/0.45 = 1333.333(repeating) rounded to nearest dollar is 1333

Check by doing 1333 x 0.45 (comes out to be 599.85)

You might be interested in

Increase the number 60 by 30%

Natalija [7]

Answer:

78

Step-by-step explanation:

10% = 6

⬇️ x3

30% = 18

⬇️ Add onto 60

60+18=78

4 0

2 years ago

Read 2 more answers

Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

4 0

3 years ago

In a cave, a stalactite gets 44 millimeters longer each year. this year it is 72 centimeters long. how many years until it is 1

iragen [17]

Answer:

6.36 years (the .36 repeats), so rounded is 6.4.

Step-by-step explanation:

First, I'm going to convert all measurements to meters.

Since 1000 mm = 1 m, divide 44 by 1000.

44/1000 = 0.044 m

Since 100 cm = 1 m, divide 72 by 100.

72/100 = 0.72 m

Next, I'm going to setup an equation using y = mx + b.

b is the beginning amount which is 0.72.

m in the equation represents the rate which is 0.044.

y represents the total which is 1.

Plugin the numbers and solve for x.

1 = 0.044x + 0.72

1 - 0.72 = 0.044x + 0.72 - 0.72

0.28 = 0.044x

0.28/0.044 = 0.044x/0.044

6.36 = x

7 0

2 years ago

What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The

max2010maxim [7]

<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

${\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}$

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

(6x+10°)
(x+17°)
(4x-34)°

According to sum theory

${\boxed{\sf The \:sum\:of\:angles=180°}}$

Substitute the values

$\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180$

Remove brackets

$\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180$

Together like polynomials and constants

$\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180$

$\qquad \quad{:}\longmapsto\tt 11x-7=180$

Interchange sides

$\qquad \quad{:}\longmapsto\tt 11x=180+7$

$\qquad \quad{:}\longmapsto\tt 11x=187$

$\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}$

Simplify

$\qquad \quad{:}\longmapsto\tt x=17$

$\therefore\sf The \:value\:of\:x\;is\:17.$

8 0

3 years ago

Find the tenth term in each sequence. -1,2/3,7/3,4,17/3

Luba_88 [7]

It'a an arithmetic sequence:

$a_1=-1\\\\a_2=-1+\dfrac{5}{3}=-\dfrac{3}{3}+\dfrac{5}{3}=\dfrac{2}{3}\\\\a_3=\dfrac{2}{3}+\dfrac{5}{3}=\dfrac{7}{3}\\\\a_4=\dfrac{7}{3}+\dfrac{5}{3}=\dfrac{12}{3}=4\\\\a_5=4+\dfrac{5}{3}=\dfrac{12}{3}+\dfrac{5}{3}=\dfrac{17}{3}\\\vdots\\\\\text{The general formula for nth term of an arithmetic sequence}\\\\a_n=a_1+(n-1)d\\\\\text{We have}\ a_1=-1\ \text{and}\ d=\dfrac{5}{3}.\\\\\text{Substitute}\\\\a_n=-1+(n-1)\left(\dfrac{5}{3}\right)=-1+\dfrac{5}{3}n-\dfrac{5}{3}=\dfrac{5}{3}n-\dfrac{3}{3}-\dfrac{5}{3}$

$\boxed{a_n=\dfrac{5}{3}n-\dfrac{8}{3}}$

5 0

3 years ago