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2 years ago

Which number is greater 5 or 1

Mathematics

1 answer:

11111nata11111 [884]2 years ago

5 0

Answer:

Step-by-step explanation:

5 is greater than 1 because it is further to the right from zero on the number line

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MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

Ivenika [448]

$- 3 \sqrt{180 {x}^{5}y } = - 3 \sqrt{36 {x}^{4} \times 5xy } = - 18 {x}^{2} \sqrt{5xy}$

$5 \sqrt{108xy {z}^{2} } = 5 \sqrt{36 {z}^{2} \times 3xy } = 30z \sqrt{3xy}$

$3x \sqrt{x {y}^{10} {z}^{7} } = 3x \sqrt{ {y}^{10} {z}^{6} \times xz } = 3x {y}^{5} {z}^{3} \sqrt{xz}$

$\sqrt{ {x}^{3} } = \sqrt{ {x}^{2} \times x } = x \sqrt{x}$

$\sqrt{x {y}^{3}z } = y \sqrt{xyz}$

$\sqrt{18 {x}^{2}y } = \sqrt{9 {x}^{2} \times 2y } = 3x \sqrt{2y}$

$\sqrt{32 {x}^{4} {y}^{2} } = \sqrt{16 ({ {x}^{2} })^{2} {y}^{2} \times 2 } = 4 {x}^{2} y \sqrt{2}$

$2 \sqrt{16 {x}^{7} {y}^{3} {z}^{4} } = 2 \sqrt{ {4}^{2} {x}^{6} {y}^{2} ( { {z}^{2} )}^{2} \times xy } = 8 {x}^{3} y {z}^{2} \sqrt{xy}$

${x}^{2} \sqrt{ {x}^{3} {y}^{2} } = {x}^{2} \sqrt{ {x}^{2} {y}^{2} \times x } = {x}^{3} y \sqrt{x}$

Answer: ......

Ok done. Thank to me :>

5 0

1 year ago

Raina has 3 buckets.

Daniel [21]

Answer:

30/3=10

so every bucket gets 10 liters

Step-by-step explanation:

4 0

2 years ago

What is the maximum value of the objective function, P, with the given constraints?

Gala2k [10]

Answer:

C. 450

Step-by-step explanation:

Plot the solution area for the system of four inequalities

$\left\{\begin{array}{l}4x+y\le 16\\x+y\le 10\\x\ge 0\\y\ge 0\end{array}\right.$

You'll get the quadrilateral with vertices at points (0,0), (0,10), (2,8) and (4,0).

The maximum value of the function can be at vertices, so

$P=25x+45y\\ \\P(0,0)=25\cdot0+45\cdot 0\\ \\P(0,10)=25\cdot 0+45\cdot 10=450\\ \\P(2,8)=25\cdot 2+45\cdot 8=50+360=410\\ \\P(4,0)=25\cdot 4+45\cdot 0=100$

The maximum value of the function is 450 at point (0,10)

7 0

3 years ago

Five times the sum of a number and 6

Aleks04 [339]

5(x+6) is the answer you are looking for. x represents a number

6 0

2 years ago

Whoever does it I will Give a special thanks to them. Just answer 4.

Stolb23 [73]

For this question you have to solve the equation backwards.
A = 1/2 x (b1 + b2) x h
In order to get rid of the 1/2 (since it's division) multiply each side by 2
now we have: 2A = (b1 + b2) x h
Now do the same to the get rid of the (b1 + b2) (divide each side by it)
2A/(b1 + b2) = h

4 0

2 years ago