130 divided by 2.5 equals show work

Does anyone knows how to solve thiss???

irina1246 [14]

10 thanks and i'll answer this

Step-by-step explanation:

8 0

2 years ago

Plzzzzzz helppppp asappppp ****will mark brainliest ****

Sonja [21]

ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:

Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)

Hypotenuse = √2 units.

So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.

Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.

$AB = \frac{10}{\sqrt{2}}$

$= \frac{10\sqrt{2}}{\sqrt{2}\sqrt{2}}$ to rationalize the radical

$= \frac{10\sqrt{2}}{2} = 5\sqrt{2}$

Thus, each leg is 5\sqrt{2} [/tex].

6 0

2 years ago

In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?

chubhunter [2.5K]

Answer:

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In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?

A.) 0.4

B.) -0.4

C.) 2

D.) -2

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Step-by-step explanation:

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# i hope it helps you

# mark me brainliest thank you

8 0

2 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$