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dmitriy555 [2]
3 years ago
12

What is the volume of a pyramid 5 feet tall if its base is a square 4 feet by 4 feet

Mathematics
2 answers:
Sauron [17]3 years ago
4 0
Given:
height (h) = 5 feet
base length (l) = 4 feet
base width (w) = 4 feet
Now,
Volume of a pyramid = \frac{l*w*h}{3}

                               = \frac{5*4*4}{3}

                               = \frac{80}{3}

                               = 26.67 ~ ft^{3}  ----> rounded to the nearest hundredth 
Katen [24]3 years ago
4 0
V = (1/3) * Base Area * height.

   =  (1/3) * (4*4) * 5 =  80/3  cubic feet.

=  26. 6667 cubic feet.
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lina2011 [118]

Answer:

x = 5.1

Step-by-step explanation.

Our first step is to find all the angles. If b = 91 degree and c is 38, a. has to be 51 because all triangles add up to 180 degree. Because we have both B and b, we can use sine law.

a/A     13/sin91      c/38

we can use b in this situation.

The legnth  of a is 10.1.

So,  x-5 would be 5.1

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3 years ago
Bob bought 24 hockey tickets for $83. Adult tickets cost $5.50 and child tickets cost $2.00. How many child tickets did he buy?
Digiron [165]

Answer:

14 kid tickets

10 adult tickets

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8 0
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Ostrovityanka [42]

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4 0
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Read 2 more answers
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
3 years ago
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