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Mademuasel [1]
3 years ago
12

In the year 2003, a person bought a new car for $21500. For each consecutive year

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0
I believe the answer would be $12,900
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John and his son are building a boxcar for a group competition. According to the rules of the competition, the length of the car
kozerog [31]

Answer:

x ≥ y + 2

0.50 (x) (x+3) + 2.25 (4) (y) ≤ 50

Step-by-step explanation:

x = width of the car

x+3 = length of the car

y = radius of the car

The width must be at least 2 inches greater than the radius, so:

x ≥ y + 2

The total cost must be no more than $50, so:

0.50 (x) (x+3) + 2.25 (4) (y) ≤ 50

6 0
3 years ago
Simple easy question please help ASAP will mark brainliest! Hector is competing in a 42- mile bicycle race. He has already compl
olganol [36]

Answer and Explanation: The answer and explanation is in the image.

4 0
2 years ago
What is the answer to -5m-18=52
Scilla [17]
The answer is

-5m-18=52
-5=52+18
-5=70
70:5=14
M=15

Hope it help
3 0
3 years ago
Identify the 27th term of an arithmetic sequence where a1 = 38 and a17 = -74. . A. -20.5 . B. -151 . C. -22.75 . D. -144 . .
Dennis_Churaev [7]
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a1 = 38 and a17 = -74
</span>

an = a1 + (n-1)d
-74 = 38 + (17-1)d
d = -7

The 27th term is calculated as follows:

a27 = a1 + (n-1)d
a27= 38 + (27-1)(-7)
a27 = -144 -----------> OPTION D
7 0
4 years ago
A 20-meter long cable is used to support a telephone pole, holding the pole to make the pole perpendicular to the ground. If the
natka813 [3]

Answer:

17.32 meters

Step-by-step explanation:

We realize the cable is the hypotenuse and then that height would be the new side, the measurement would not change once hypotenuse is found.

60 deg is the lower angle as it meets the ground base.

Sin (60) = 0.8660254038 x 20 = 17.32m

0.86 reduction = a  

We use Sin (60) = a  a x 20 to find the pole as above.

We use Tan (60) x base to find 20m to check hypotenuse if base was given = length of floor x tan(60) etc.

4 0
3 years ago
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