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Mademuasel [1]
2 years ago
12

In the year 2003, a person bought a new car for $21500. For each consecutive year

Mathematics
1 answer:
lilavasa [31]2 years ago
4 0
I believe the answer would be $12,900
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355 divided 14 hiksdjkndndf
vaieri [72.5K]

Answer:

Rounded to the nearest whole number is 25

4 0
2 years ago
1. Kyle and John are twins who decided to plan an imaginary trip that started with cliff jumping. There were two different spots
Vikki [24]

Answer:

a) Δx = -35ft

b) Δx = -25ft

c) Kyle traveled 10ft more than John

Step-by-step explanation:

We define a coordinate reference system() in which y = 0 corresponds to the water surface.

a) The initial position of Kyle in our coordinate reference system is:

   x_{o} = 20 ft

   and his final position is:

   x_{f} = -15 ft

   Therefore, he traveled

   Δx = x_{f} - x_{o} = -15 - 20 = -35 ft

b) The initial position of John in our coordinate reference system is:

   x_{o} = 15 ft

   and his final position is:

   x_{f} = -10 ft

   Therefore, he traveled

   Δx = x_{f} - x_{o} = -10 - 15 = -25 ft

c) Then, Kyle traveled 10ft more than John

 

6 0
3 years ago
What is the constant rate of change of (5,80) (4,64) and (6,96)
sveticcg [70]

Answer:

16

Step-by-step explanation:

The existence of the constant rate of change is given the ratio of y to x is the same. Then:

k_{1} = \frac{80}{5}

k_{1} = 16

k_{2} = \frac{64}{4}

k_{2} = 16

k_{3} = \frac{96}{6}

k_{3} = 16

In consequence, the constant rate of change is 16.

8 0
2 years ago
Rita car can travel 35 miles on one gallon of gas she needs she needs to trace 157.5 miles how many gallons of gas will she need
Otrada [13]
You would do 157.5/35 to find how much gas she needs

157/35=4.5
She'll need 4.5gallons of gas
3 0
3 years ago
Some people took part in a game. The frequency shows information about their scores.
Marizza181 [45]

Answer:

The mean = 17.54

Step-by-step explanation:

Form a table as below;

<u>Interval         Frequency{f}      Midpoint of frequency{x}          fx    </u>

1-7                    19                         4                                            76

8-10                  14                         9                                            126

11-15                  15                         13                                           195

16-20                20                        18                                           360

21-35                 10                        28                                          280

36-50                13                         43                                          559

Sum                   91                                                                        1596

The mean  of grouped data = Sum of { Interval Midpoint * Frequency } /Sum of frequency

The mean= 1596 / 91

The mean = 17.54

5 0
3 years ago
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