Question

If (he)={(0,1),(2,3),(-4,1)}, find h^-1(x)

Answer 1

The given function is

$h(x) = \{ (0,1), (2,3), (-4, 1) \}$

The inverse function is

$h^{-1}(x) = \{ (1,0), (3,2), (1,-4)\}$

To get the inverse, we swap each x and y coordinate.

The rule is $(x,y) \to (y,x)$

So that's why the point (0,1) becomes (1,0) for instance.