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zalisa [80]
2 years ago
10

Which of these strategies would eliminate a variable in the system of equations?

Mathematics
1 answer:
mariarad [96]2 years ago
4 0

Answer:

<em>Multiply the bottom equation by -3/2 then add the equations. </em>

<em>Multiply the top equation by-3. then add the equations </em>

<em> </em>

Step-by-step explanation:

Given the simultaneous equation

2x- 6y=6  ... 1

6x - 4y = 2 ... 2

To eliminate a variable, we have to make the coefficient of one of the variable to be the same.

Multiply equastion 1 by -3

-6x+18y= -18  

6x - 4y = 2

Add the result:

-6x + 6x + 18y-4y = -18+2

18y-4y = -18+2

14y = -18

y = -9/7

Another way is to Multiply the bottom equation by -3/2 then add the equations.

Multiplying equation 2 by -3/2 will give;

6x(-3/2) - 4y(-3/2) = 2(-3/2)

-9x + 6y = -3

Add to equation 1;

2x- 6y=6

-9x + 2x + 0 = -3+6

-7x = 3

x = -3/7

Hence the correct two options are;

<em>Multiply the bottom equation by -3/2 then add the equations. </em>

<em>Multiply the top equation by-3. then add the equations </em>

<em> </em>

<em></em>

<em></em>

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