All categories

2 years ago

Which of these strategies would eliminate a variable in the system of equations?

Mathematics

1 answer:

mariarad [96]2 years ago

4 0

Answer:

Multiply the bottom equation by -3/2 then add the equations.

Multiply the top equation by-3. then add the equations

Step-by-step explanation:

Given the simultaneous equation

2x- 6y=6 ... 1

6x - 4y = 2 ... 2

To eliminate a variable, we have to make the coefficient of one of the variable to be the same.

Multiply equastion 1 by -3

-6x+18y= -18

6x - 4y = 2

Add the result:

-6x + 6x + 18y-4y = -18+2

18y-4y = -18+2

14y = -18

y = -9/7

Another way is to Multiply the bottom equation by -3/2 then add the equations.

Multiplying equation 2 by -3/2 will give;

6x(-3/2) - 4y(-3/2) = 2(-3/2)

-9x + 6y = -3

Add to equation 1;

2x- 6y=6

-9x + 2x + 0 = -3+6

-7x = 3

x = -3/7

Hence the correct two options are;

Multiply the bottom equation by -3/2 then add the equations.

Multiply the top equation by-3. then add the equations

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%7B10%7D%5Ex%20%3D%205" id="TexFormula1" title=" {10}^x = 5" alt=" {10}^x = 5" align="absmi

My name is Ann [436]

Answer:

below

Step-by-step explanation:

10ˣ = 5

applying log to both sides

xlog 10 = log5

x = 0•699

8 0

3 years ago

Geometry: complete this proof, ASAP!!!!!!!!!!!!!!!! It’s urgent

mixas84 [53]

Answer:

1.ABC is equilateral triangle because all sides are equal

3.because they are the joined figure of a triangle

7 0

2 years ago

describe a situation in which a formula could be used more easily if it were rearranged. Include the formula in your description

pshichka [43]

I need to find the length of something when I am given the volume, width, and height.

v=lwh
l = v/wh

Hope this helps!

5 0

3 years ago

Read 2 more answers

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago

The school that Perry goes to is selling tickets to a spring musical. On the first day of ticket salesthe school sold 2 adult ti

ch4aika [34]

Answer:

Adult ticket: $12

Child ticket: $11

4 0

3 years ago