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larisa [96]
2 years ago
8

Find each sum or difference for 381 1/10 -214 43/100

Mathematics
2 answers:
BartSMP [9]2 years ago
6 0

Answer:

The circled part is the answer.

Luba_88 [7]2 years ago
5 0

Answer:

6789475

Step-by-step explanation:

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PLEASE HELP!<br> NO LINKS!<br> I only need help on letter d!!
IRINA_888 [86]
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3 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
Please need help on this
dedylja [7]

Answer:

Step-by-step explanation:

the a = 30

4 0
3 years ago
Amanda is cooking a cake.the recipe calls for 6 cups sugar.she accidentally put in cups.how many extra cups did she put in?
GenaCL600 [577]
................................... "she accidently put in cups" ???? But she calls for 6 cups sugar. how many cups did she accidently put it?
8 0
3 years ago
Read 2 more answers
Here are 7 numbers.
SIZIF [17.4K]

Answer:

3.06

I hope this helps you :)

4 0
2 years ago
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