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larisa [96]
2 years ago
8

Find each sum or difference for 381 1/10 -214 43/100

Mathematics
2 answers:
BartSMP [9]2 years ago
6 0

Answer:

The circled part is the answer.

Luba_88 [7]2 years ago
5 0

Answer:

6789475

Step-by-step explanation:

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ONLY 1% OF PEOPLE GET THIS RIGHT AND One rabbit saw six elephants while he was going to the river. Each elephant saw two monkeys
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Answer:

31 animals

Step-by-step explanation:

1 rabbit + 6 elephants + 6*2=12monkeys + 12 parrots = 31 animals

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3 years ago
Which expression is equivalent to the one below? 6 ÷ 5<br><br>A 6:1/5<br>B 5:1/6<br>C 5/6<br>D 30​
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Answer:

option A

Step-by-step explanation:

6:1/5 can also be written as 6/1÷5 which equals to 6÷5

7 0
3 years ago
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Find the measure, in degrees, of angle x in this figure.
Alona [7]
X in this equation equals 140°
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3 years ago
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How much do 4 dozen buttons cost if they pay $18 for 144 buttons?
zzz [600]

Answer:

Step-by-step explanation:

.125 for 1 button

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7 0
3 years ago
Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

8 0
3 years ago
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