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3 years ago

Find the missing angle for the equilateral triangle below .

Mathematics

1 answer:

creativ13 [48]3 years ago

6 0

Answer:

All equilateral triangles have angles equal to 60°.

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Is the product of two imaginary numbers always imaginary?

Diano4ka-milaya [45]

No. i*i = -1

2i*3i=-6

now if they meant complex numbers the answer is still no

(2+4i)(2-4i) = 4-8i+8i-16 = -12

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3 years ago

Which of the following has a graph that is a straight line? (4 points) Equation 4: y = 3x3 Equation 3: y = 2x2 + 4 Equation 1: y

Ray Of Light [21]

The equation of the line: y = mx + b.

Therefore your answer is Equation 1: y = 2x + 7.

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3 years ago

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a person who take 40 paces to cover 20m finds that a square field has a side that is 520 paces long .calculate the length of the

Hoochie [10]

Look at picture for explanation

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3 years ago

Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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3 years ago

Fernando has a bag of beads in five different colors: purple, blue, green, green, orange, and gray. The table below shows the re

zavuch27 [327]

Answer: 6

Step-by-step explanation:

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3 years ago