We use Chargaff's rule to get the answer.
[A] + [G] = [C]+ [T].
[A] + [G] + [C] + [T] = 100%
Where is A is Adenine, G is Gaunine, T is Thymine and C is Cytosine.
In DNA, Adenine always pairs with Thymine, and Guanine always pairs with Cytosine.
Therefore if Thymine is 35%, then Adenine will also be 35% to make 70% in total.
The remaining percentage will be 100% - 70% = 30%.
The 30% will be shared equally among Cytosine and Guanine, at 15% each. Therefore Cytosine will be 15%
Asexual means by self sexual means from opposite genders
Answer:
The correct answer is - Ψ = ΨS + ΨP.
Explanation:
The movement of the water in a solution where is two different concentrations present can be determined by measuring the water potential (Ψ).
Water potential (Ψ) can be determined by the equation that depends on these two factors osmotic potential represent by ΨS and pressure potential represent by ΨP.
Ψ = ΨS + ΨP.
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
