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KIM [24]
3 years ago
15

There are six multiple-choice questions on an exam, each with four possible answers. (a) Determine the number of possible answer

sequences for the six questions.
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Possible\ Answers = 4096

Step-by-step explanation:

Given

Questions = 6

Options = 4 each

Required

Determine the number of possible answers

<em>The first question has 4 possible answers</em>

<em>The second has 4 possible answers</em>

<em>The third has 4 possible answers</em>

<em>The fourth question has 4 possible answers</em>

<em>The fifth has 4 possible answers</em>

<em>The sixth question has 4 possible answers</em>

<em />

Possible\ Answers = 4 * 4 * 4 * 4 * 4 * 4

Possible\ Answers = 4^6

Possible\ Answers = 4096

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Kate wants to buy a TV that has a price of $450. Kate decides to start saving after
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Answer:

450 = (15·x) -50

Step-by-step explanation:

You know that the TV cost $450

She already have $50

you know she saves $15/month

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3 years ago
Draw an example of a shape that has at least one right angle one angle less than a right angle and one angle greater that a righ
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The angles are called acute obtuse and right angle.
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4 years ago
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A line passes through the point (-8, -4) and has a slope of 5/2. Write and equation in slope intercept form for this line.
nirvana33 [79]

Answer:

i know this isn't the answer but this should help...

Step-by-step explanation:

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3 years ago
The function h is defined by h(x) =<br> 6+ x<br> -5+ 3x<br> Find h(5a).
almond37 [142]

Answer:

(6+5a)/ (-5 +15a)

Step-by-step explanation:

h(x) = (6+x) / (-5+3x)

Let x = 5a

h(5a) =(6+5a) / (-5+3*5a)

        = (6+5a)/ (-5 +15a)

3 0
3 years ago
You are given that cos(A)=−35, with A in Quadrant II, and cos(B)=817, with B in Quadrant I. Find cos(A−B). Give your answer as a
neonofarm [45]

cos (A - B) is 36/85

<h3>How to simply the identity</h3>

Expand cos(A - B) with the identity

You get, cos(A - B) = cos(A) cos(B) + sin(A) sin(B)

Since A is in quadrant II, so sin(A) > 0,

B is in quadrant I, so sin(B) > 0.

Using the Pythagorean identity, we get

cos²(A) + sin²(A) = 1  

Make sin A the subject of formula

sin(A)^{2} =  (\sqrt{(1 - (-3/5})²)

Find the square root of both sides, square root cancels square

sin A = 4/5

Repeat the same for the second value

sin A^{2} = \sqrt{(1- 8/17)^2}

sin A = 15/17

Substitute values into cos(A - B)

cos(A - B) =  cos(A) cos(B) + sin(A) sin(B) = (-3/5) * 8/17 + 4/5 * 15/17

cos (A - B) = 36/85

Therefore, cos (A - B) is 36/85

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

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