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3 years ago

Choose Yes Or No To Tell if the fraction 4/9 will make each equation True.

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

5 0

Answer:

true, true, false, true

Step-by-step explanation:

(4/9)*63=28

(4/9)*18=8

(4/9)*96=42.666667

(4/9)*36=16

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2 years ago

The system of equations shown below is graphed on a coordinate grid:

Rufina [12.5K]

Answer:

4x 3 - 6 4 is the answer

Step-by-step explanation:

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3 years ago

Which linear function has the same y-intercept as the one that is represented by the graph? On a coordinate plane, a line goes t

Zolol [24]

The line which is having same y intercept as the line which passes through points (-4,0) and (0,3) is y=2x+3.

Given Points through which the line passes through are (-4,0) and (0,3)

We have to find the equation whose y intercept is equal to the y intercept of the line whose points given above.

First of all we have to find the y intercept of the line which passes through (-4,0) and (0,3). Equation of line is :

y-y1=(y2-y1)/(x2-x1)*(x-x1)

y-0=(3-0)/(0+4) *(x+4)

y=3/4(x+4)

y -intercept exists where x=0

put x=0

y=3

So the options are:

y=2x-4

y=2x-3

y=2x+3

y=2x+4

By putting the value of x in all options we will find

y=-4

y=-3

y=3

y=4

So the third option is correct.

Hence the line whose y-intercept matched with the given line is y=2x+3.

Learn more about line at brainly.com/question/13763238

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2 years ago

What is the slope of a line perpendicular to the line:<br><br> y = -2/3x + 5

Rus_ich [418]

1.5

Opposite reciprocal of -2/3

5 0

3 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago