The formula for distance problems is: distance = rate × time or d = r × t
Things to watch out for:
Make sure that you change the units when necessary. For example, if the rate is given in miles per hour and the time is given in minutes then change the units appropriately.
It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.
The following diagrams give the steps to solve Distance-Rate-Time Problems. Scroll down the page for examples and solutions. We will show you how to solve distance problems by the following examples:
Traveling At Different Rates
Traveling In Different Directions
Given Total Time
Wind and Current Problems.
Answer:
4x 3 - 6 4 is the answer
Step-by-step explanation:
i took the test in flvs
The line which is having same y intercept as the line which passes through points (-4,0) and (0,3) is y=2x+3.
Given Points through which the line passes through are (-4,0) and (0,3)
We have to find the equation whose y intercept is equal to the y intercept of the line whose points given above.
First of all we have to find the y intercept of the line which passes through (-4,0) and (0,3). Equation of line is :
y-y1=(y2-y1)/(x2-x1)*(x-x1)
y-0=(3-0)/(0+4) *(x+4)
y=3/4(x+4)
y -intercept exists where x=0
put x=0
y=3
So the options are:
By putting the value of x in all options we will find
y=-4
y=-3
y=3
y=4
So the third option is correct.
Hence the line whose y-intercept matched with the given line is y=2x+3.
Learn more about line at brainly.com/question/13763238
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1.5
Opposite reciprocal of -2/3
Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have

This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point 
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0



square root both sides


the positive value is
