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Mars2501 [29]
4 years ago
7

Which expression is equivalent to -14-6

Mathematics
2 answers:
andre [41]4 years ago
5 0

Answer:

-14+(-6)

-6+(-14)

Step-by-step explanation:

Vlada [557]4 years ago
5 0
-14+ (-6) you just need to witch the signs
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Blank over five plus eighteen over twenty equals thirty over twenty
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3 and i use flvs too, also that pfp is fire

Step-by-step explanation:

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What is the length of Line segment B C, rounded to the nearest tenth? 13. 0 units 28. 8 units 31. 2 units 33. 8 units.
Len [333]

The length of the line segment BC is 31.2 units.

<h2>Given that</h2>

Triangle ABC is shown.

Angle ABC is a right angle.

An altitude is drawn from point B to point D on side AC to form a right angle.

The length of AD is 5 and the length of BD is 12.

<h3>We have to determine</h3>

What is the length of Line segment BC?

<h3>According to the question</h3>

The altitude of the triangle is given by;

\rm Altitude = \sqrt{xy}

Where x is DC and y is 5 units.

Then,

The length DC is.

\rm Altitude = \sqrt{xy}\\&#10;\\&#10;12 = \sqrt{(DC) \times 5}\\&#10;\\&#10;\sqrt{DC } = \dfrac{12}{\sqrt{5}}\\&#10;\\&#10;

Squaring on both sides

\rm DC = \dfrac{144}{5}\\&#10;\\&#10;DC = 28.8

Considering right triangle BDC, use the Pythagorean theorem to find BC:

\rm BC^2 = DC^2+BD^2\\\\  BC^2 = (28.8)^2+(12)^2\\&#10;&#10;\\&#10;BC = \sqrt{829.44+144}\\&#10;\\&#10;BC = \sqrt{973.44}\\&#10;\\&#10;\rm BC = 31.2 \ units

Hence, the length of the line segment BC is 31.2 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/26252222

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2 years ago
Which set of real numbers only contain integers?
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3. 2/9,2,0

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(2/9,2,0,-7)

4 0
3 years ago
Is the graph increasing, decreasing, or constant?
djyliett [7]

Answer:

It is increasing.

Step-by-step explanation:

Given the graph of a straight line, there are several ways to find its equation.

Method 1: This method works only if the y intercept is visible.

Find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Get b from inspection of the y intercept of the graph.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 2: This method works even if the y intercept is not visible.

As in method 1, find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Substitute the number that you obtained for m into the equation y = m x + b. Also, take one of the points, say (x1, y1), and substitute its coordinates into the equation. This gives:

y1 = m x1 + b

It may not look like it, but this equation has only one variable, b, and you can easily solve for it.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 3: This method has the advantage that it uses only algebra, not geometry, and can be applied to any type of function, not just the straight line:

Find two points, (x1, y1) and (x2, y2), that are on the line. Take the first point, (x1, y1), and substitute it into the straight line equation, y = m x + b. This gives:

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Similarly, take the second point, (x2, y2), and substitute it into the straight line equation, y = m x + b. This gives:

y2 = m x2 + b

Together, these two equations constitute a system of two equations in the two unknowns, m and b. We can solve them for m and b using the elimination method. To be specific, if we subtract the first equation from the second, then b is eliminated and we get the equation:

y2 − y1 = m x2 − m x1,

which, when solved for m, gives the same equation as in the other two methods, namely:

Find b by back-substitution. To be specific, substitute the number that you obtained for m into one equation of the system of equations, say into y1 = m x1 + b. It may not look like it, but this equation has only one variable, b, and you can easily solve for it

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3 years ago
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