The median means the middle number.
First, you put them in order from least to greatest.
Then, you look to see which number is in the middle.

Since there are only four numbers given, you have to go in between two of the numbers.

The median is in between 22,000 and 24,000.

20,000 22,000 _ 24,000 26,000

The number that is equally between 22,000 and 24,000 is 23,000.

The median for the set of data is $23,000.

Hope this helps!

8 0

4 years ago

4. The hypotenuse of a 30°- 60°- 90° right triangle measures 22 cm. What are the lengths of the longer leg and shorter leg? 4. T

s2008m [1.1K]

We are given the a right triangle and the interior angles of the triangle. We use some trigonometric functions to solve the length of the remaining legs. We calculate as follows:

let a and b the length of the legs

cos 30 = a / 22
a = 19.05 cm

sin 30 = b / 22
b = 11 cm

Hope this answers the question. Have a nice day.

5 0

3 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

3 0

3 years ago

you and your friend are collecting seashells on the beach. You collect 20 more shells than your friend collects. Together, you a

Anestetic [448]

You first add 92+20. You will get 112. So 112 seashells collected.

8 0

3 years ago