<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
What is the distance between a point at (-3,4) and a point at (2,-5) ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Let the two points be A and B .
And, let the distance be P .
Now, the distance P between the point A (-3,4) and the point B (2,-5) is




<h3>The distance between a point at (-3,4) and a point at (2,-5) is <u>1</u><u>0</u><u>.</u><u>3</u> . [Answer]</h3>
5-(-1) or you could simplify it further to 6
Answer:
5y = x
Step-by-step explanation:
15 miles = 3 hours
Divide by 3 on both sides to find how many miles he/she can run in 1 hour.
15 miles = 3 hours ⇒ 5 miles = 1 hour
Therefore, the equation is just 5y = x.
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Answer:
h = 1 2/3
Step-by-step explanation:
1/2 (5-2h) = h/2
Multiply each side by 2
(5-2h) = h
Add 2h to each side
(5-2h +2h) = h+2h
5 = 3h
Divide by 3
5/3 = 3h/3
5/3 =h
1 2/3 = h
Check
1/2 (5-2*5/3) = 5/3/2
1/2 ( 5 - 10/3) = 5/6
1/2 ( 15/3 - 10/3) = 5/6
1/2 ( 5/3) = 5/6
5/6 = 5/6
Answer:
N= 9, PV= 1658
Step-by-step explanation: