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vovikov84 [41]
3 years ago
8

If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9?​

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer: If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9? Cell D9 must contain a 0.

Step-by-step explanation: hope this helped!

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84 is 60% of what number?
mariarad [96]
I'm pretty sure that it is 140. Hope I helped!
7 0
3 years ago
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Write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral A. B. C. D IN THE PICTURE
Mice21 [21]

Answer:

The sequence of transformation is reflected across the y-axis and translated 2 units down

Step-by-step explanation:

Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) translate h units to the right

∴ Its image is (x + h , y)

- If point (x , y) translate h units to the left

∴ Its image is (x - h , y)

- If point (x , y) translate k units up

∴ Its image is (x , y + k)

- If point (x , y) translate k units down

∴ Its image is (x , y - k)

* Now lets solve the problem

∵ The vertices of figure ABCD are:

  A (-1 , 3) , B (1 , 0) , C (2 , 3) , D (1 , 4)

∵ The vertices of figure A"B"C"D" are:

  A" (1 , 1) , B" (-1 , -2) , C" (-2 , 1) , D" (-1 , 2)

* Lets compare between ABCD and A"B"C"D"

∵ All x-coordinates has opposite signs

  -1 ⇒ 1 , 1 ⇒ -1 , 2 ⇒ -2 , 1 ⇒ -1

∴ The ABCD is reflected across the y-axis

∵ All y-coordinates subtracted by 2

 3 ⇒ 1 , 0 ⇒ -2 , 3 ⇒ 1 , 4 ⇒ 2

∴ The ABCD is translated 2 units down

* The sequence of transformation is reflected across the y-axis

  and translated 2 units down

5 0
3 years ago
A submarine changes its position by −7 meters every second. What is the change in the submarine's position after 300 seconds?
Hoochie [10]
If you take -7*300 is should equal  -2100
5 0
3 years ago
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Given the expression (8 + 6i) − (−2 + 7i), perform the indicated operation and write the answer in the form a + bi
Oliga [24]
We can distribute the negative to get 8 + 6i + 2 - 7i, and we can simplify that to get 10 - i.
---
Hope this helps!
6 0
3 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
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