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2 years ago

If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9?

1 answer:

7 0

Answer: If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9? Cell D9 must contain a 0.

Step-by-step explanation: hope this helped!

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A box contains 18 green marbles and 8 white marbles. If the first marble chosen was a white marble, what is the probability of c

murzikaleks [220]

Answer:

7/25

Step-by-step explanation:

Original contents of the box:

18 green marbles

8 white marbles

Contents of the box after drawing 1 white marble:

18 green marbles

7 white marbles

Total: 25 marbles

p(white) = (number of white marbles)/(total number of marbles)

p(white) = 7/25

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2 years ago

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Prove: cos(3x)=sin(2x)

Vesnalui [34]

Answer:

Step-by-step explanation:

Step-by-step explanation:

By taking ( x = 18°)

L.H.S

cos(3x)=sin(2x)

cos(3x) = cos( 3X18°)= cos (54°)

= cos[ 90° - (2x18°)] ∵[ 90°- (2x18°) = 54°]

= ∴ sin ( 2x18°)

As (x = 18°)

= sin (2x) = R.H.S

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2 years ago

Solve this system of equations. 12x − 18y = 27 4x − 6y = 10

kifflom [539]

Answer:

no solution

Step-by-step explanation:

12x − 18y = 27

4x − 6y = 10

Multiply the second equation by -3 so we can eliminate x

-3(4x − 6y) = 10*-3

-12x +18y = -30

Add the first equation to this new equation

12x − 18y = 27

-12x +18y = -30

------------------------

0 = -3

This is not a true equation, so there is no solution

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2 years ago

How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

3 0

3 years ago

If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9?​

If a cell displaying #DIV/0! contains the formula =C2/D9, what must be the value of cell D9?