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kondaur [170]
3 years ago
8

The intersection of a triangle and a line could be a segment True or False

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

false

                                                                                                                                                   vdvfvfddfvgggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

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Which is greater 5 8/10 or 58/10
NARA [144]
This is a trick question. the answer is neither, they are both equivalent to one another :)
8 0
3 years ago
1 . fraction bar a fraction in which the numerator is smaller than the denominator 2 . numerator the number under the fraction l
11Alexandr11 [23.1K]

Answer:

The number under the fraction line tells how many equal parts the whole was broken into

8 0
2 years ago
What is the first term for an arithmetic sequence with a12 = 56 and a21=101?
Alenkinab [10]
The first term is -43.

Explanation:

an = a + (n - 1)d

a12 = a + 11d = 56, first equation
a21 = a + 20d = 101, second equation

Subtract the second equation from the first equation, cancelling +a and -a
11d - 20d = 56 - 101
-9d = -45
d = 5

Subtitute d into the first equation
a + 99 = 56
a = -43

a refers to the first term, hence the first term is -43.
4 0
3 years ago
Given: 6(2x−2)≥3x+2(x+1)<br> Prove: x≥2
lyudmila [28]
I don’t know to be honest
8 0
3 years ago
Read 2 more answers
∫<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bxdx%7D%7B%28x%5E%7B2%7D%2B4%29%5E%7B3%7D%20%7D" id="TexFormula1" title="\frac{xdx}{
photoshop1234 [79]

Substitute u=x^2+4 and du=2x\,dx. Then the integral transforms to

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}

Apply the power rule.

\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C

Now put the result back in terms of x.

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}

3 0
2 years ago
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