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kondaur [170]
3 years ago
8

The intersection of a triangle and a line could be a segment True or False

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

false

                                                                                                                                                   vdvfvfddfvgggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

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Write x2 - 12x + 8 = 0 in vertex form.
antiseptic1488 [7]
(x-4)^2-19=y
you first add the three to the other side, then add 16 on both sides, make the left side x-4 squared, and lastly you subtract 19 from both sides.
3 0
3 years ago
Read 2 more answers
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
3 years ago
Read 2 more answers
9 millimeters to centimeters
Oxana [17]
9 millimeters= 0.9 centimeters
6 0
3 years ago
Problem page the sum of two numbers is 56 . the smaller number is 16 less than the larger number. what are the numbers?
igomit [66]
Create equations using the given information
1) x+y=56
2) y=x-16
Substitute the value of y into the 1st equation and simplify
1)x+x-16=56
   2x=72
   x=36
Substitute the value of x into the 1st equation and simplify
1)x+y=56
   36+y=56
   y=20

Answer: 20 and 36

8 0
3 years ago
What is 524.47 rounded to the nearest tenth?
kolbaska11 [484]
The tenth place is the first number to the right of a decimal. To determine if you're rounding or not, check the hundred's place, 2 numbers to the right of a decimal, for 5 or higher. If it's .45, round to .5, if it's .44, round to .4
Your answer is 524.5, which is B.)
3 0
4 years ago
Read 2 more answers
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