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Gekata [30.6K]
3 years ago
13

Expand and simplify (4 + 2)(6-12) Give your answer in the form b+cV2

Mathematics
1 answer:
Crank3 years ago
3 0

Note: Consider the expression is (4+\sqrt{2})(6-\sqrt{2}).

Given:

(4+\sqrt{2})(6-\sqrt{2})

To find:

The value of given expression in the form of b+c\sqrt{2}.

Solution:

We have,

(4+\sqrt{2})(6-\sqrt{2})

Using distributive property, we get

=4(6-\sqrt{2})+\sqrt{2}(6-\sqrt{2})

=4(6)+4(-\sqrt{2})+\sqrt{2}(6)+\sqrt{2}(-\sqrt{2})

=24-4\sqrt{2}+6\sqrt{2}-2

On combining like terms, we get

=(24-2)+(6\sqrt{2}-4\sqrt{2})

=22+2\sqrt{2}

On comparing with b+c\sqrt{2}, we get

a=22,b=2

Therefore, the required form is 22+2\sqrt{2}.

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Given that point A is the midpoint of line segment ED, where E( -1,9) and A(4,5), what is the location of point D?
yuradex [85]

Answer:

  D(9, 1)

Step-by-step explanation:

A being the midpoint means its coordinates satisfy ...

  A = (E + D)/2

Solving for D, we find ...

  D = 2A -E

  = 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)

  D = (9, 1)

8 0
4 years ago
Find the sine ratio of angle Θ. Hint—Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no sp
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Answer:

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2 years ago
What is the correct answer?
iragen [17]

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F

Step-by-step explanation:

5 0
3 years ago
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When an octave is divided into twelve equal steps, a chromatic scale results. The ratios between sucessive notes is
alukav5142 [94]

Answer: They would be A.

Step-by-step explanation: Don't take my word for it 100%

7 0
3 years ago
Diego was asked to plot these points: (−50,0) ( − 50 , 0 ) , (150,100) ( 150 , 100 ) , (200,−100) ( 200 , − 100 ) , (350,50) ( 3
Irina18 [472]

Answer:

We have the points:

(-50, 0)

(150, 100)

(200, -100)

(350, 50)

(-250, 0)

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The smallest value is x = -250

The largest value is x = 350

Then the interval that we choose for the x-axis should include these two values (so we can plot the points)

Then we need to use, at least, the interval [-250, 350]  (A interval that is a little bit larger than that will be easier to read, but that is the minimum he needs to do the plot)

Now let's do the same with the values of the y-components.

The smallest value is y = - 100

The largest value is y = 100

Then the vertical interval should be [-100, 100] or a little bit larger, like in the horizontal case.

We also can see that the values of x and y seem to jump in multiples of 50, then each unit of the grid could represent 50 units, so it is easier to plot. (These are also called intervals, and also theses will depend on each individual axis, but in this case we could use the same for both of them, because it works well for both axis)

4 0
3 years ago
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