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tekilochka [14]
2 years ago
7

△ABC is similar to △XYZ . Also, angle A measures 45° and angle C measures 60°. What is the measure of angle Y? Show all your cal

culations!

Mathematics
2 answers:
Mila [183]2 years ago
3 0
<span>75° Since △ABC is similar to △XYZ, that means that angle A equals angle X, angle B equals angle Y, and angle C equals angle Z. So let's look at the data we have. Angle A measures 45° and angle C measures 60°. That means that angle B measures 180° - 45° - 60° = 75° since all triangles have 180° and we've been told the measurement of two of the angles. And since angle Y is equal to angle B (which we just calculated), that means that angle Y is also equal to 75°</span>
kifflom [539]2 years ago
3 0

Answer:

Just took the test and got it right :)))

Step-by-step explanation:

Look at the image down below!!

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A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit
Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

R(1) = 100(\frac{2}{5}.1 )

R(1) = 100(\frac{2}{5} )

R(2) = 100(\frac{2}{5}.2 )

R(2) = 100(\frac{4}{5} )

\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )

\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]

\Delta R= 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100(\frac{2}{5} .0)

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = 100(\frac{2}{5}.10 )

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

500=100(\frac{2}{5}.t )

\frac{500}{100}=\frac{2}{5}.t

t = \frac{500.5}{100.2}

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0
2 years ago
Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}
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Start with a line segment connecting two points, A and B. \dfrac{DA}{BA}=3 means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with \dfrac{DB}{BA}=2, or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, \dfrac{AB}{CB}=\dfrac12, so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let d be the length of AB. Then the length of CD in terms of d is 4d. We have the coordinates of C and D, and the distance between them is \sqrt{(4-0)^2+(0-4)^2}=4\sqrt2. So

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The slope of the line through C and D is

\dfrac{0-4}{4-0}=-1

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Step-by-step explanation:

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