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BartSMP [9]
3 years ago
13

Determine whether the triangles are congruent by SSS or SAS. If not congruent, write "not congruent." b) If congruent, write a c

ongruency statement.
Mathematics
2 answers:
DanielleElmas [232]3 years ago
6 0

Answer:

sss: congruent

SAS: non congruent

Step-by-step explanation:

If all three pairs of corresponding sides are congruent, the triangles are congruent. This congruence shortcut is known as side-side-side (SSS). Another shortcut is side-angle-side (SAS), where two pairs of sides and the angle between them are known to be congruent.

Ulleksa [173]3 years ago
4 0

Answer:

sss is all sides are the same length, in the same order, and if they both have those side they are congruent. sas is two sides that are connected by an angle, and if the sides connected by that angle match the other triangle then they will be congruent

Step-by-step explanation:

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0=1+1/3y in slope intercept formula
ElenaW [278]

Answer:

y = -3

Step-by-step explanation:

- Subtract 1 to both sides

-1 = 1/3y

- Multiply both sides by 3

y = -3

Slope is 0 since there is no x variable

If this helped, please feel free to pick this answer as the brainliest! Thank you very much and have a wonderful day!

8 0
3 years ago
Read 2 more answers
Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)
DENIUS [597]
By the chain rule,

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

We have

\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}
\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}

\dfrac{\mathrm dx}{\mathrm dt}=7\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t
\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t

So we have

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)
\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}
3 0
3 years ago
I don't know how to do #86-#88. Any help?
SOVA2 [1]
86 and 87 utilize the Pythagorean theorem. Where those tangent lines meet the circle forms a right angle. So you have a side length of 6 and a hypotenuse of 22. So the missing side length is 21.16.  For 87, its the same thing, but you have the 2 legs but are missing the hypotenuse.
3 0
3 years ago
What is the slope-intercept form of m= -4
just olya [345]

Answer:

y = - 4x

Step-by-step explanation:

The slope-intercept form of a line is y = mx + b. In this case, m is - 4 and no b value is given.

8 0
3 years ago
Read 2 more answers
Find the value of x in each quadrilateral.
elena-14-01-66 [18.8K]

If i am correct, these values should add to 360, so I do it by

140 + 110 + 62 = 312

360 - 312 = 48

So the value of the last side must equal 48.

Your answer would be x = -9. Proof:

If 9 is filled in, you would have

(3 - 5(-9))

(3 - (-45))

48

Then

48 + 140 + 110 + 62 = 360!

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

4 0
3 years ago
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