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Sveta_85 [38]
2 years ago
8

Determine whether the function is linear (0,1) (-2,-1) (-4,1)

Mathematics
1 answer:
Brut [27]2 years ago
6 0

Answer:

No, this is not a linear function

Step-by-step explanation:

If you graph each point, you will notice that none of the three points line up together in one line with a consitstant slope.

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When I double my number and add eight , I get my number plus twelve. What is my number?
Butoxors [25]
Your answer is 2 as if you double 2 you get 4 and add 8 oh get 12
8 0
3 years ago
In a study by the Texas A & M University, found there were 23,000 prairie dogs in Texas in 2000. By 2010, the number has inc
Dima020 [189]

let x=k

D=dog

T=Taxes

I=increase P=population

solve k

d=23,000

t=2000

d=2.3e^

divide both sides by 2

after year is,2000+k2-2.3

=1.999.7

k2- 23,000=

k-x

or

k2-2

5 0
3 years ago
At 2pm on Tuesday the temperature was -12
cestrela7 [59]

Answer:

-2×h

Step-by-step explanation:

because it drops-2 by hour so multiply-2 by the difference of hours

8 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
Solve for x..........10 points*
Ivanshal [37]

Answer:

\huge\boxed{\sf x = 12}

Step-by-step explanation:

8x + 34 = 130 <u>(Vertical Angles are Equal)</u>

Subtract 34 to both sides

8x = 130 - 34

8x = 96

Divide both sides by 8

x = 96 / 8

x = 12

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
3 years ago
Read 2 more answers
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