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3 years ago

Help me with this please only number 13 & 14

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

6 0

Step-by-step explanation:

13 would be plotted on the x-axis, quadrant II. 14 would be on the x-axis, quadrant I

Studentka2010 [4]3 years ago

3 0

Answer:

The name of the app is Desmos and it provides you a graphing calculator where you can plot points as well as equations.

Hope this helps!

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What is 6(7-2p) =12p+42

mafiozo [28]

answer:

p = 0

step-by-step explanation:

6 (7-2p) = 12p + 42

42 - 12p = 12p + 42

+12p +12p

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42 = 24p + 42

-42 -42

_____________

0 = 24p

_ ___

24 24

0 = p

<em>hope this helps! ❤ from peachimin (aka kayla)</em>

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3 years ago

If the simple interest on $6000 for 9 years is $2160, then what is the interest rate?

NISA [10]

Step-by-step explanation:

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2 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1

6 0

4 years ago

Consider a home mortgage of $225,000 at a fixed APR of 4.5 % for 30 years. a. Calculate the monthly payment. b. Determine the

White raven [17]

<u>The formula for the monthly payment</u>.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}$ , where P = the principal amount, r = the monthly interest rate and n = the total number of months.

Here annual interest rate is given as 4.5%

So, the monthly interest rate $=\frac{4.5\%}{12}= 0.375\% = 0.00375$

Total number of months $= (30*12)months=360 months$

Also given that, the principal amount is $225000

a. So, the monthly payment will be.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}\\ \\ M= \frac{225000(1+0.00375)^3^6^0*0.00375}{(1+0.00375)^3^6^0 -1}\\ \\ M= \frac{225000(1.00375)^3^6^0*0.00375}{(1.00375)^3^6^0 -1} \\ \\ M \approx 1140$

Thus, the monthly payment will be approximately $1140

b. The <u>total amount paid</u> over the term of the loan will be: $\$ 1140*360 months = \$ 410400$

c. As the principal amount was $225000 , so the amount of interest $= (\$ 410400- \$ 225000)= \$ 185400$

So, the percentage of amount that is paid toward the principal $=\frac{225000}{410400}*100\% =54.82\%$

and the percentage of amount that is paid toward the interest $=\frac{185400}{410400}*100\%=45.18\%$

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3 years ago

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Gnom [1K]

Angle TVU = 1/2 (120 - 12) = 108/2 = 56°

Therefore, the correct answer is D.

7 0

3 years ago