Answer:
0.75 mg
Step-by-step explanation:
From the question given above the following data were obtained:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Amount remaining (N) =.?
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Number of half-lives (n) =?
n = t / t₁/₂
n = 6/6
n = 1
Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Number of half-lives (n) = 1
Amount remaining (N) =.?
N = 1/2ⁿ × N₀
N = 1/2¹ × 1.5
N = 1/2 × 1.5
N = 0.5 × 1.5
N = 0.75 mg
Thus, 0.75 mg of the sample is remaining.
Answer:
C
Step-by-step explanation:
I did this question today, pls lmk if u get it right
Answer:
2.2+3(3.4)
=2.2+10.2
=12.4
Step-by-step explanation:
2*2=4 first you multiply
4-1=3 then subtract
3+3=6 now you add and that is your answer =6
Answer:
f(1) = 81
Step-by-step explanation:
given is f(n + 1) = 1/3f(n)
f(3) = 9
ayou need to find f(0) before you can answer what is f(1).
Just start by applying for...
n=0
f(0+1) = 1/3 * f(0)
f(1) = 1/3 * f(0)
n=1
f(1+1) = 1/3 * 1/3*f(0)
f(2) = 1/9 * f(0)
n=2
f(2+1) = 1/3 * 1/9* f(0)
f(3) = 1/27 * f(0)
But it is given that f(3) = 9 so substitute this in the line above to calculate the value of f(0)....
9 = 1/27 * f(0)
Multiply left and right of the = sing by 27 gives
f(0) = 27 * 9
f(0) = 243
We already know this next line because we started with n=0
f(1) = 1/3 * f(0)
Substitute f(0) = 243 in the line above to finally calculate the value of f(1).
f(1) = 1/3 * 243
f(1) = 81
