3x - y = 9
4x + y = 5
---------------add
7x = 14
x = 14/7
x = 2
3x - y = 9
3(2) - y = 9
6 - y = 9
-y = 9 - 6
-y = 3
y = -3
C. (2,-3) is a solution to the system of linear equations
Step-by-step explanation:
Answer attached..
<h2><u>MARK ME AS BRAINLIST</u> </h2>
There are four queens in a deck of cards, so the probability of drawing a queen is 4/52. There is also a 4/52 chance of drawing a two. Because you can draw either a two or Queen, you add the probability of each.
4/52 + 4/52 = 8/52
8/52 can be simplified to 2/13
The equation of the perpendicular line is 13y=27-x
Step-by-step explanation:
Writing the given equation to slope-intercept form.
y=− 1 3 x+6
The slope of this line is 13
The perpendicular slope is -1/13
Using the new slope and the given point into the slope-intercept form to find the y-intercept.
4=-1/13(2)+c
2=-1/13+c
c=27/13
y=-1/13x+27/13
So the equation of the perpendicular line is 13y=27-x
Answer:
<em>The plane landed after 9.4 minutes.</em>
Step-by-step explanation:
<u>Function Modeling</u>
The initial altitude of a plane arriving at JFK International Airport is 30,000 ft.
It then began its descent at a rate of 3,200 feet per minute.
Let's call t the number of minutes since the descent started. If each minute the plane descends 3,200 feet, then after t minutes it descends 3,200t.
This must be subtracted from the initial altitude, thus the altitude H is written as:
H = 30,000 - 3,200t
When the plane landed, its altitude was H=0, thus:
0 = 30,000 - 3,200t
Adding 3,200t:
3,200t = 30,000
Dividing by 3,200:
t = 30,000/3,200
t = 9.375 minutes
Rounding to the nearest tenth:
The plane landed after 9.4 minutes.
