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2 years ago

Please I’ll give thanks

Mathematics

1 answer:

Genrish500 [490]2 years ago

3 0

Choice D

The slopes of two perpendicular lines are negative reciprocals of each other.

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Find the value of x.<br> 105°/15x

Natalija [7]

$\text{The two angles are supplementary, so their measures add up to 180 degrees.}$

$~~~~~~15x+105 = 180\\\\\implies 15x = 180 -105\\\\\implies 15x = 75\\\\\implies x =\dfrac{75}{15}\\\\\implies x = 5$

8 0

1 year ago

Students in a middle school must choose to take either Band or Chorus. In a given academic year, 60% of the pupils choose Band a

grigory [225]

Pupils that chose Band: 60%
Pupils that chose Chorus: 40%
Boys in band: 70%
Boys in chorus: 30%
Probability of choosing boy = Probability of boy in band + Probability of boy in chorus
P = 0.6 x 0.7 + 0.4 x 0.3
P = 0.54
The answer is D.

3 0

2 years ago

A line segment has endpoints A(4, 8) and B(2, 10). The point M is the midpoint of AB. What is an equation of a line perpendicula

Vera_Pavlovna [14]

I)

The Midpoint M of the line segment AB is found using the Midpoint formula:

$M=( \frac{4+2}{2} , \frac{8+10}{2})=(3, 9)$

ii)

the slope of the line through A and B is found by the slope formula:

$m= \frac{y_1-y_2}{x_2-x_1}= \frac{10-8}{2-4}= \frac{2}{-2}=-1$

iii)

the product of the slopes of 2 perpendicular lines is -1, so the slope of the line perpendicular to the line through A and B is -1/(-1)=1

iv)

the equation of the line with slope 1, which contains point M(3, 9) is found by the slope point form equation of a line:

y-9=1(x-3)

y-9=x-3

y=x+6

Answer: y=x+6

7 0

2 years ago

HELP ASAP

serg [7]

The equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.

<h3>What is the equation of line?</h3>

The equation of the line is the way of representation of a line in the equation form.

The equitation of the lines represents the line by the set of points on which the line lies or passes through in the coordinate system.

The formula to find equation of line is,

(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)

Here, x and y are the coordinate and subscript (1,2) used for the first and second point.

The points from which the line passes through are (2,5) and (-2,-3). Put the values,

(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)

(y-(-2))={(-3-5)/(-2-2)}(x-2)

y+2={-8/-4}(x-2)

y+2=2(x-2)

y+2=2x-4

y=2x-4-2

y=2x-6

Thus, the equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.

Learn more about the equation of line here;

brainly.com/question/13763238

#SPJ1

3 0

2 years ago

What is the discontinuity of (x^2 + 3x - 4)/(x^2 + x - 12)?

zvonat [6]

The discontinuity occurs when the denominator is equal to zero, as it has "infinite" slope, and thus is not a real value or point.

x^2+x-12

x^2+4x-3x-12

x(x+4)-3(x+4)

(x-3)(x+4)

So discontinuities occur when x=-4 and x=3

4 0

2 years ago

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