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omeli [17]
3 years ago
7

The greater of two consecutive even integers is 20 more than twice the smaller. find the integers

Mathematics
1 answer:
dezoksy [38]3 years ago
3 0

Step-by-step explanation:

I guess this is correct and pls let me know if it is incorrect

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2 years ago
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Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

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8 0
1 year ago
What is the simplified form of the following expression? 10abc^2 sqrt 49a^2b^2c^2
Elodia [21]
10abc^2\sqrt{49a^2b^2c^2}=70a^2b^2c^3 

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

10abc^2\sqrt{49a^2b^2c^2} 

\sqrt{49a^2b^2c^2}=7abc 

7\cdot \:10aabbc^2c 

70aabbc^2c 

70a^2bbc^2c 

70a^2b^2c^2c 

70a^2b^2c^3
4 0
2 years ago
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